1.

There is an air bubble of radius R inside a drop of water of radius 3R. Find the ratio of gauge pressure at point B to that at point A.

Answer»

`(1)/(2)`
`(1)/(4)`
`(1)/(3)`
1

Solution :`P_(B)-P_(0)=(2T)/(3R),P_(A)=P_(B)+(2T)/(R),P_(A)-P_(0)=(2T)/(3R)+(2T)/(R)=2T[(4)/(3R)],(P_(B)-P_(0))/(P_(A)-P_(0))=(1)/(4)`


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