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There is one coil of resistance 5 Omega and magnetic flux linked with the coil is changed by Delta phi in 0.1 s. Induced current is found to decrease linearly from 4 A to zero in the given time interval. Calculate value of Delta phi in Wb. |
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Answer» Average CURRENT `i_(AV) = 2 A` Average emf induced `e_(av)= (DELTAPHI)/(Deltat)` Average current `i_(av)= e_(av)//R= (1)/(R)(Deltaphi)/(Deltat)` Substituting VALUES we get the following: `2= (1)/(5) xx (Deltaphi)/(0.01)` `Deltaphi= 1Wb` Hence answer is 1. |
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