There is one uniformly charged hollow metal sphere of radius r. The po

1.	There is one uniformly charged hollow metal sphere of radius r. The potential difference between a point on the surface of this sphere and a point at a distance 2r from the surface is V. What will be the electric field intensity at a point at a distance 3r from the centre?
Answer» Let centre of the hollow sphere(of radius r) is O and potential at centre is V_o. Let point is P from where centre is at fistance 2r and potential at this point is Vp. According to the question V_o-Vp=V Now V_o=kq/r ,where q is the charge on hollow sphere. V_P=kq/2r Vo-Vp=(kq/2r)=V q=(2rV/k) Electric field at distance 3r from centre is kq/r² Putting value of q here we get E=2V/r This is the final answer. I hope it helps Let centre of the hollow sphere(of radius r) is O and potential at centre is V_o. Let point is P from where centre is at fistance 2r and potential at this point is Vp. According to the question V_o-Vp=V Now V_o=kq/r ,where q is the charge on hollow sphere. V_P=kq/2r Vo-Vp=(kq/2r)=V q=(2rV/k) Electric field at distance 3r from centre is kq/r² Putting value of q here we get E=2V/r This is the final answer. I hope it helps

There is one uniformly charged hollow metal sphere of radius r. The potential difference between a point on the surface of this sphere and a point at a distance 2r from the surface is V. What will be the electric field intensity at a point at a distance 3r from the centre?

Answer»

Let centre of the hollow sphere(of radius r) is O and potential at centre is V_o.

Let point is P from where centre is at fistance 2r and potential at this point is Vp.

According to the question V_o-Vp=V

Now V_o=kq/r ,where q is the charge on hollow sphere.

V_P=kq/2r

Vo-Vp=(kq/2r)=V q=(2rV/k)

Electric field at distance 3r from centre is kq/r²

Putting value of q here we get

E=2V/r This is the final answer.

I hope it helps