1.

There will be three different flourine-flourine distance in molecules CF_2 (C )_2CH_2.Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet.Round off your answer to the nearest whole number. (Given that C-F bond length =134 pm, C=C bond length =134 pm sqrt3=1.73)

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SOLUTION :
`d_1=2xx134xxsin60^@ "PM"=231.8"pm"=232"pm"`


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