1.

Therefore are 6xx10^(19) electrons per unit cubic metre of pure semiconductor. What will be the number of holes for this semiconductor of dimension 1 cm xx 1 cm xx 2 cm?

Answer»

`6xx10^(19)`
`1.2xx10^(14)`
`12xx10^(14)`
`2xx10^(6)`

Solution :`1.2xx10^(14)`
VOLUME of crystal `v=l xx b xx h`
`=1xx1xx2xx10^(-6)m^(3)`
`=2xx10^(-6)m^(3)`
In PURE semiconductor `n_( e)=n_(h)=6xx10^(19)m^(-3)`
`THEREFORE` Total number of holes in crystal,
`N=n_( e)V=6xx10^(19)xx2xx10^(-6)=12xx10^(13)`


Discussion

No Comment Found

Related InterviewSolutions