Thereis a conductor with cavity of radius R as shown in figure. A point charge Q is placed at R//2 distance from centre of cavity. A point P is at r distance from centre of conductor. Then,

Thereis a conductor with cavity of radius R as shown in figure. A poin

1.	Thereis a conductor with cavity of radius R as shown in figure. A point charge Q is placed at R//2 distance from centre of cavity. A point P is at r distance from centre of conductor. Then,
Answer» <P>CHARGE density at iner SURFACE of cavity will be NON uniform charge density at surface of CONDUCTOR will be uniform electric field at point `P` is `Q/(4pi epsilon_(0)r^(2))` force on charge `Q` is non zero Solution :Electric field lines kill of on surface on conductor.

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Thereis a conductor with cavity of radius R as shown in figure. A point charge Q is placed at R//2 distance from centre of cavity. A point P is at r distance from centre of conductor. Then,

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