1.

Thespecificconductance(orconductivity ) of0.014MNaBrsolutionis 3.16 xx 10^(-4) S cm^(-1) .Findthe molarconductivity of thesolution .

Answer»


Solution :Concetrationof the solution= 0.014 M NaBr
Specificconductance= conductivity = K
`=3.16 XX 10^(-4)S cm^(-1)( or Omega^(-1)cm^(-1))`
Molarconductivity = `^^_(m) = ?`
`^^_(m) = (k xx 1000)/( C)`
` =(3.16 xx 10^(-1)xx 1000)/( 0.014)`
`mol L ^(-1)`
`= 22.57 S cm^(2) mol^(-1)(or Omega^(-1)cm^(2)mol^(-1))`


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