They three years ago?The ages of Leena and Heena are in the ratio 7:5.

1.	They three years ago?The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of theirages will be 9: 7. Find their present ages.
Answer» ANSWER: Therefore, The Leena’s age is 28 years and Heena’s age is 20 years. Step-by-step explanation: The AGES of Leena and Heena are in the ratio 7:5. Thus there ages are, Leena 7x and Heena 5x Ten years hence, the ratio of their ages will be 9:7. 10 year hence their ages will be Leena’s age 7x + 10 Heena’s age 5x + 10 The ratio of their ages : 7x + 10 / 5x + 10 = 9 / 7 Cross MULTIPLICATION : 9 ( 5x + 10 ) = 7 ( 7x + 10 ) 45x + 90 = 49x + 70 45x - 49x = 70 - 90 —5x = -20 5x = 20 x = 20/5 x = 4 The rational is 4 .Their respective ages. Leena’s age 7x = 7 × 4 = 28 years Heena’s age 5x = 5 × 4 = 20 years Therefore, The Leena’s age is 28 years and Heena’s age is 20 years. Hope it's HELPS you!!! Plz Mark me as a brainliest.

They three years ago?The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of theirages will be 9: 7. Find their present ages.

Answer»

Therefore, The Leena’s age is 28 years and Heena’s age is 20 years.

Step-by-step explanation:

The AGES of Leena and Heena are in the ratio 7:5.

Thus there ages are, Leena 7x and Heena 5x

Ten years hence, the ratio of their ages will be 9:7.

10 year hence their ages will be

Leena’s age 7x + 10

Heena’s age 5x + 10

The ratio of their ages :

7x + 10 / 5x + 10

= 9 / 7

9 ( 5x + 10 ) = 7 ( 7x + 10 )

45x + 90 = 49x + 70

45x - 49x = 70 - 90

—5x = -20

5x = 20

x = 20/5

x = 4

The rational is 4

.Their respective ages.

Leena’s age 7x = 7 × 4 = 28 years

Heena’s age 5x = 5 × 4 = 20 years