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Thickness of a cylinder measured using a screw gauge of least count 0.01 cm is found to be equal to 0.80 cm. Thepercentage error in measurement is2.5%1.25%5%0.5%​

Answer»

Step-by-step explanation:GIVEN,         Thickness (t)= 0.802cm         Least count= 0.001 cmnow error in MEASURING t=(0.802±0.001)So, percentage error=0.001/0.802×100%                                 =0.1246%                                 ≈0.125%VOLUME of CYLINDER V=πr2L∴ Percentage error in volume⇒VΔV​×100=r2Δr​×100+lΔl​×100                           =2(2.00.01​)×100+5.00.1​×100                           =(1+2)=3 .



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