1.

Thin glass (refractive index 1.5) lens has optical power of - 5 D in air. Its optical power in a liquid medium with refractive index 1.6 will be :

Answer»

1 D
`- 1 D`
25 D
`- 25 D`

Solution :(a) `(1)/(f_(m)) = ((1.5)/(1.6) - 1) ((1)/(R_(1)) - (1)/(R_(2)))`
and `(1)/(f_(a)) = (1.5 - 1) ((1)/(R_(1)) - (1)/(R_(1)))`
Then`f_(m) = 160 cm`
`P_(m) = (mu)/(f_(m)) = (1.6)/(1.6) = 1D`


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