1.

This is from the chapter sequence and series​

Answer»

Step-by-step explanation:

The NTH term in this SERIES is equal to (n²+n)

SUM of all TERMS in this series

= (1²+2²+....+n²)+(1+2+....n)

= \frac{n(n + 1)(2n + 1)}{6}  +  \frac{n(n + 1)}{2}

= \frac{n(n + 1)(n + 2)}{3}



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