1.

Three are 4 white 5 black and 2 red balls in an urn. Favourable cases of three different colour balls will be –(A) 9(B) 24(C) 12(D) 7

Answer»

Answer is (B) 24

White balls = 4, Black balls = 3

and Red balls = 2

Favourable cases of three different colour balls

= 4 × 3 × 2 = 24



Discussion

No Comment Found

Related InterviewSolutions