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Three are 4 white 5 black and 2 red balls in an urn. Favourable cases of three different colour balls will be –(A) 9(B) 24(C) 12(D) 7 |
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Answer» Answer is (B) 24 White balls = 4, Black balls = 3 and Red balls = 2 Favourable cases of three different colour balls = 4 × 3 × 2 = 24 |
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