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Three blocks are connected as shown in the fig on a horizontal frictionless table if `m_(1)=1kg, m_(2)=8kg, m_(3)=27 kg` and `T_(3)=36N, T_(2)` will be: A. 18 NB. 9 NC. `3.375 N`D. `1.75 N` |
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Answer» Correct Answer - B `a=F//(m_(1)+m_(2)+m_(3))=36//(1+8+27)=1m//s^(2)` `T_(2)=(m_(1)+m_(2))a=(1+8)xx1=9N` |
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