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Three blocks of equal masses (each `3kg`) are suspended by weightless strings as shown. If applied force is `100N`,then `T_(1)` is equal to `(g=10m//s^(2))` A. `130 N`B. `190 N`C. `100 N`D. `160 N` |
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Answer» Correct Answer - A `T_(1)=F+mg` |
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