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Three capacitors 2muF, 5muF and 10muF are joined in (a) series, (b) paralle. Find the equivalent capacitance. |
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Answer» SOLUTION :(a) SERIES Data SUPPLIED, `C_(1)=2muF, C_(2)=5muF, C_(3)=10muF` `1/C_(s)=1/C_(1)+1/C_(2)+1/C_(3)=1/2+1/5+1/10` `C_(s)=1.25muF` (B) Parallel `C_(p)=C_(1)+C_(2)+C_(3)=2+5+10=17muF` |
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