1.

Three capacitors of 2 pF, 3 pF and 4 pF are connected in parallel. What is the total capacitance of a network ?

Answer»

9 pF
`(12)/(13) ` pF
`(13)/(12)pF`
`(1)/(9)` pF

Solution :`C_(1)=2 pF, C_(2) =3 pF, C_(3)= 4 pF`
For PARALLEL CONNECTION
`C_(eq)=C_(1)+C_(2)+C_(3)= 2+3+4= 9 pF`


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