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Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel (a) What is the total capacitance of the combination? (b) Determine the charge on each capacitor if the combination is connected to a 100 V supply |
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Answer» Solution :For all parallel combination of the capacitors equivalent capacitance, `C_(p) = C_(1) +C_(2)+C_(3)` where `C_(1)=2` pF `C_(2)= 3 pF` and `C_(3) = 4 pF ` =2+3+4 =9 pF `= 9xx10^(-12)` F (B)  SUPPOSE, the `q_(1),q_(2)` and `q_(3)` are the charges on capacitor `C_(1), C_(2)` and `C_(3)` respectively and supply voltage is 100 V. `:. q_(1)=C_(1)V=2xx10^(-12) xx100=2xx10^(-10)C` `q_(2)=C_(2)V= 3XX10^(-12)xx10^(-12)xx100=3xx10^(10)C ` `q_(3)= C_(3)V= 4xx10^(-12)xx100= 4xx10^(10)C` |
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