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Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. (a) What is the total capacitance of the combination ? (b) Determine the charge on each capacitor if the combination is connected to a 100 V supply. |
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Answer» Solution :Here ` C_1 = 2 pF, C_2 = 3 pF, C_3 = 4 pF` (a) TOTAL capacitance of PARALLELCOMBINATION `C = C_1 + C_2 + C_3= 2 + 3 + 4 = 9 pF= 9 xx 10^(-12) F.` (b) In parallel combination potential difference across each CAPACITOR= V = 100V `:. Q_1= C_1 V = 2 xx 10^(-12)xx 100 = 2 xx 10^(-10) C` `Q_2= C_2 V= 3 xx 10^(-12) xx100 = 3 xx 10^(-10) C` and `Q_3= C_3 V = 4 xx 10^(-12) xx 100 = 4 xx 10^(-10) C`. |
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