1.

Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. (a) What is the total capacitance of the combination? (b) Determine the charge on each capacitor if the combination is connected to a 100 V supply. 

Answer»

(a) Capacitances of the given capacitors are C1 = 2 pF, C2= 3 pF and 4 pF 

For the parallel combination of the capacitors, equivalent capacitor CT is given by the algebraic sum, 

C' = 2 + 3 + 4 = 9 pF

Therefore, total capacitance of the combination is 9 pF. 

(b) Supply voltage, V = 100 V 

The voltage through all the three capacitors is same = V = 100 V 

Charge on a capacitor of capacitance C and potential difference V is given by the relation, q = VC … (i) 

For C = 2 pF, 

Charge = VC = 100 x 2 = 200 pC = 2 x 10-10 C

For C = 3 pF, 

Charge = VC = 100 x 3 = 300 pC = 3 x 10-10 C

For C = 4 pF, 

Charge = VC = 100 x 4 = 400 pC = 4 x 10-10 C


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