InterviewSolution
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Three cards are drawn at random (without replacement) from a well shuffled pack of 52 playing cards. Find the probability distribution of number of red cards. Hence find the mean of the distribution. |
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Answer» Let the number of red card in a sample of 3 cards drawn be random variable X. Obviously X may have values 0,1,2,3. Now P(X = 0)= Probability of getting no red card = 26C3/52C3 = 2600/22100 = 2/17 P(X = 1)= Probability of getting one red card and two non-red cards = (26C2 x 26C2)/52C3 = 8450/22100 = 13/34 P(X = 2)= Probability of getting two red card and one non-red card = (26C2 x 26C1)52C3 = 8450/22100 = 13/34 P(X = 3)= Probability of getting 3 red cards = 26C3/52C3 = 2600/22100 = 2/17 Hence, the required probability distribution in table as
= 13/34 + 26/34 + 6/17 = (13 + 26 + 12)/34 = 51/34 = 3/2 |
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