1.

Three cards are drawn at random (without replacement) from a well shuffled pack of 52 playing cards. Find the probability distribution of number of red cards. Hence find the mean of the distribution.

Answer»

Let the number of red card in a sample of 3 cards drawn be random variable X. Obviously X may have values 0,1,2,3.

Now P(X = 0)= Probability of getting no red card = 26C3/52C3 = 2600/22100 = 2/17

P(X = 1)= Probability of getting one red card and two non-red cards =  (26C2 x 26C2)/52C3 = 8450/22100 = 13/34

P(X = 2)= Probability of getting two red card and one non-red card =  (26C2 x 26C1)52C3 = 8450/22100 = 13/34

P(X = 3)= Probability of getting 3 red cards = 26C3/52C3 = 2600/22100 = 2/17

Hence, the required probability distribution in table as

X0123
P(X)2/1713/3413/342/17


∴ Required mean = E(X) = ∑pixi = 0 x 2/17 + 1 x 13/34 + 2 x 13/34 + 3 x 2/17

= 13/34 + 26/34 + 6/17 = (13 + 26 + 12)/34 = 51/34 = 3/2



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