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Three charges each`+q`, are placed at the corners of an isosceles triangle `ABC` of sides `BC` and `AC, 2a, D` and `E` are the mid-points of `BC` and `CA`. The work done in taking a charge `Q` from `D` to `E` is A. `(eqQ)/(8piepsilon_(0)a)`B. `(qQ)/(4piepsilon_(0)a)`C. zeroD. `(3qQ)/(4piepsilon_(0)a)` |
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Answer» Correct Answer - c Here, `AC = BC` As `D` and `E` are the third mid points of `BC` and `CA`, the potential of these points should be equal. `V_(D)=V_(E )=V` The work done in talking a charge `Q` from `D` to `E` `W= Q[V_(E )-V_(D)]=Q[V-V]=0` |
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