1.

Three charges 'q' each are vertices of an equilateraltriangle of side 'r'. How much charge shouldbe placedat the centroid so that the system remains in equilibrium.

Answer»

Solution :Force on the charge .q. is `SQRT(3) (1)/(4pi in_(0)) .(q^(2))/(r^(2)) =F_(1)`
A charge .Q. is placed at its centroid. Force APPLIED by this charge on .q. is `(1)/(4pi in_(0)) .(3Qq)/(r^(2)) =F_(2)`.
If `F_(1)=F_(2)` the systemremains in EQUILIBRIUM.

`sqrt(3) (1)/(4pi in_(0)) (q^(2))/(r^(2)) =(1)/(4pi in_(0)) (3Qq)/( r^(2)) `
`Q= -(q)/(sqrt(3))`


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