1.

Three closed vessels A, B and C are at the same temperature T and contain gases which obey the Maxwell distribution of speed. Vessel A contains only O_(2), B only N_(2) and C a mixture of equal quantities of O_(2) and N_(2). If the average speed of O_(2) molecules in vessel A is v_(1), that of the N_(2) molecules in vessel B is v_(2), the average speed of the O_(2) molecules in vessel C will be

Answer»

`(v_(1)+v_(2))//2`
`v_(1)`
`(v_(1)v_(2))^(1//2)`
`v_(1)//2`

Solution :AVERAGE speed of gas molecules,
`v_(AV)=sqrt((8RT)/(piM_(0))),v_(av)propsqrt(T)`
It depends on temperature and molecules mass.
At same temperature average speed of `O_(2)` molecule is same in vessel A and C and is EQUAL to `v_(1)`.


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