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Three coins are tossed simultaneous. Find the probability of getting only two heads. |
Answer» Three coins are tossed simultaneously the possible outcomes are. HHH, HHT, HTH, THH, HTT, THT, TTH, TTT. Total number of all possible outcomes = 8. The favourable outcomes of getting 2 heads exactly = HHT, HTH, THH ∴ The number of favourable outcomes = 3 ∴ The required probability = \(\frac { 3 }{ 8 }\). |
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