1.

Three coins are tossed together. Find the probability of getting:(i) exactly two heads(ii) at least two heads(iii) at least one head and one tail(iv) no tails

Answer»

When 3 coins are tossed together,

Total no. of possible outcomes = 8 {HHH, HHT, HTH, HTT, THH,THT, TTH, TTT}

(i) Probability of an event = (No. of favorable outcomes)/(Total no. of possible outcomes)

Let E ⟶ event of getting exactly two heads

No. of favourable outcomes = 3 {HHT, HTH, THH}

Total no. of possible outcomes = 8

P(E) = 3/8

(ii) E ⟶ getting at least 2 Heads

No. of favourable outcomes = 4 {HHH, HHT, HTH, THH}

Total no. of possible outcomes = 8

P(E) = 4/8 = 1/2

(iii) E⟶ getting at least one Head & one Tail

No. of favourable outcomes = 6 {HHT, HTH, HTT, THH, THT, TTH}

Total no. of possible outcomes = 8

P(E) = 6/8 = 3/4

(iv) E ⟶ getting no tails

No. of favourable outcomes = 1 {HHH}

Total no. of possible outcomes = 8

P(E) = 1/8


Discussion

No Comment Found

Related InterviewSolutions