InterviewSolution
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InterviewSolution
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Three coins are tossed together. Find the probability of getting: (i) exactly two heads (ii) at most two heads (iii) at least one head and one tail. (iv) no tails |
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Answer» Sample space, n(S) = 8 (i) p = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{8}\) (ii) p = \(\frac{n(E)}{n(S)}\) = \(\frac{4}{8}\) = \(\frac{1}{2}\) (iii) p = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{8}\) = \(\frac{3}{4}\) (iv) p = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{8}\) |
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