Three consecutive integers are 7,8,9 Step by Step Explanation :THRE consecutive integers are such that, when they are taken in increasing order and multiplied by 2, 3, and 4, respectively, they add up to 74. How WOULD one find these numbers?Consecutive numbers are numbers that follow each other in order. They have a difference of 1 between every two numbers.Let the smallest of consecutive integer be n,Therefore, other two consecutive integers are to be n + 1 and n + 2 in increasing orderNow multiplying these three consecutive numbers with 2, 3, and 4 respectively. They become2 (n), 3 (n + 1) and 4 (n + 2)These add up to 74, means2 (n) + 3 (n + 1) + 4 (n + 2) = 742n + 3n + 3 + 4N + 8 = 749n + 11 = 749n = 74 - 119n = 63n = 63/9n = 7The smallest consecutive Integer is 7, therefore other two consecutive integers are:7 + 1 = 87 + 2 = 9Thus the three consecutive integers are 7, 8 and 9Answer the three consecutive integers are 7, 8 and 9Let the three consecutive integers be x, x+1, x+2 in increasing orderMultiply 2,3,4 respectively2(x)+3(x+1)+4(x+2)This aad up to 742(x)+3(x+1)+4(x+2)=742x+3x+3+4x+8=749x+11=749x=74-11=63X=63÷9=7Therefore the three consecutive integers are 7,8,9If it is beneficial for you, then MARK it as 'Brainliest answer' .