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three consecutive integers are such they are taken in increasing order and multiplied by 2 3 4 respectively add up to 56find this number |
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Answer» Answer: 5 , 6 and 7. Step-by-step explanation: Let the required three consecutive INTEGERS be a , a + 1 and a + 2. According to the question, When NUMBERS are multiplied by 2 , 3 and 4 they add UPTO 56. It means : ⇒ 2( a ) + 3( a + 1 ) + 4( a + 2 ) = 56 ⇒ 2a + 3a + 3 + 4a + 8 = 56 ⇒ 2a + 3a + 4a + 3 + 8 = 56 ⇒ 9a + 11 = 56 ⇒ 9a = 56 - 11 ⇒ 9a = 45 ⇒ a = 45 / 9 ⇒ a = 5 Hence the required numbers are 5 , 5 + 1 or 6 and 5 + 2 or 7. |
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