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Three designs are proposed for an engine which is to operate between 300 K and 500 K. design A is claimed to produced 3000 J of work per kcal of heat input, B is claimed to produced 2000 J and C , 1000 J. which design would you choose ? Given 1 kcal =4185 JA. A onlyB. B onlyC. AllD. C only |
Answer» Correct Answer - D Maximum value of efficiency, `eta=1-(T_(2))/(T_(1))=1-(300)/(500)=(2)/(5)` As, `eta=(W)/(Q_(1))` `W=etaQ_(1)=(2)/(5)xx1000" cal "=400xx4.2J=1680J` As no engine can produce more than 168000 J , designs A and B are not possible . Only design C is possible. |
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