1.

Three dice are thrown simultaneously. What is the probability of getting 15 as the sum? 

Answer»

As 3 dice are thrown. So total possible outcomes = 6×6×6 = 216 

For getting 15 as the sum we need this combination- 

(5, 5, 5) or (6,4,5) or (6,6,3) 

(6, 4, 5) can be arranged in 3! = 6 ways. 

(6, 4, 5) can be arranged in (3!)/(2!) = 3 ways 

∴ 10 favourable outcomes are possible. 

∴ P(E) =  \(\frac{10}{216}\)



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