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Three dice are thrown simultaneously. What is the probability of getting 15 as the sum? |
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Answer» As 3 dice are thrown. So total possible outcomes = 6×6×6 = 216 For getting 15 as the sum we need this combination- (5, 5, 5) or (6,4,5) or (6,6,3) (6, 4, 5) can be arranged in 3! = 6 ways. (6, 4, 5) can be arranged in (3!)/(2!) = 3 ways ∴ 10 favourable outcomes are possible. ∴ P(E) = \(\frac{10}{216}\) |
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