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Three dice are thrown together. Find the probability of getting a totalof at least 6. |
Answer» `6*6*6=216` `P_1=1-P` `{(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,2,2),(2,2,1),(2,1,2),(1,1,3),(3,1,1),(1,3,1)}` P(sum<6)=10/216 P(sum>6)=1-P(sum <6) `=1-10/216=206/216=103/108`. |
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