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Three digit numbers are formed with the digits 0, 2, 4, 6 and 8. Write the probability of forming a three digit number with the same digits. |
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Answer» The probability of forming 3-digit no. with digits 0, 2, 4, 6, 8 is as follows, Since it is a 3 digit no., first place cannot have 0 as it will make it a 2 digit no. \(\therefore\) 1st place can be filled in 4 ways, 2nd place in 5 ways and 3rd in 5 ways. \(\therefore\) total number = 4 x 5 x 5 = 100 The three digit numbers with same digits are 222,444,666,888 \(\therefore\) P (forming three-digit no.) = \(\cfrac{4}{100}=\cfrac{1}{25}=0.04\) |
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