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InterviewSolution
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Three equal resistors connected in series across a source of e.m.f. together dissipate 10 W power. Find the power dissipated if the same resistors are connected in parallel. |
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Answer» Solution :`P_1 = 10 W` In series COMBINATION , total resistance = 3R Power = `P_1 = (V^2)/(3R)`  In paralle combination , total resistance = R/3 `R_2 =(V^2)/(R//3)` `IMPLIES (P_1)/(P_2) =(R//3)/(3R) implies (10)/(P_2) =(R//3)/(3R)` `(10)/(P_2) =(R)/(3xx3R) =1/9 impliesP_2 `= 90 WATTS |
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