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Three fair coins are tossed simultaneously. Find the probability of getting at least one head and a least one tail. |
Answer» S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} n(S)=8 Let A: At least one head & at least one tail. A = {HTH, HHT, HTT, THH, THT, TTH}, n(A) = 6 P(A) = \(\frac{n(A)}{n(S)} = \frac{6}{8} \) = \(\frac{3}{4}\) |
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