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                                    Three forces F, F and F, are acting on particle P (shown in figure). If particle P is in equilibrium, then20145°F3 10 N | 
                            
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Answer»  If the particle is in equilibrium , then net forces in horizontal and vertical direction should be 0 so, in vertical direction 4cos45° + F2cos∅ = 10=> F2cos∅ = 10 -2√2 .... (1) in horz direction4sin(45°) = F2sin∅ ....(2)=> F2sin∅ = 2√2 now so, dividing 2 with 1 => sin∅/cos∅ = 2√2/(10-2√2) => tan∅ = 2√2/(10-2√2) now, squaring and adding 1 and 2 F2²sin²∅ +F2²cos²∅ = 8+8+100 -40√2 => F2² = 116-40√2=> F2 = √(116-40√2) N  | 
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