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Three identical charges are placed on three vertices of a square. If the force acting between q_(1) and q_2 is F_(12) and between q_(1) and q_(3) is F_(13), then= .......... |
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Answer» `1/SQRT(2)`  `F_(12) = (k(q)(q))/a^(2) = (KQ^(2))/a^(2)` and `F_(13) = (k(q)(q))/(sqrt(2)a)^(2) = (kq^(2))/(2a^(2))` `therefore F_(13)/F_(12) = 1/2` |
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