1.

Three identical metal plates of area S are at equal distances b as shown. Initially metal plate A is uncharged, while metal plates B and C have respective charges +Q_(0) and -Q_(0) initially as shown. Metal plates A and C are connected by switch K through a resistor of resistance R. the key K is closed at time t = 0 The total heat produced dissipiated by resistor of resistance R is :

Answer»

`(Q_(0)^(2)b)/(4S epsilon_(0))`
`(Q_(0)^(2)b)/(8S epsilon_(0))`
`(Q_(0)^(2)b)/(2S epsilon_(0))`
`(3Q_(0)^(2)b)/(4S epsilon_(0))`

Solution :Finally the CHARGE on either capacitor is `Q_0//2`.Hence HEAT produced is = initial P.E.-final P.E.
`=Q_0^2/(2C)-(Q_0//2)^2/(2C)-(Q_0//2)^2/(2C)=(Q_0^2b)/(4Sepsilon_0)`


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