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Three large plates are arranged as shown. How much charge will flow through the key k if it is closed? |
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Answer» `5Q//6` `q_(1)+q_(2)=2Q` `V_(AB)=V_(AC)` or `(Q_(1))/(C_(1))=(q_(2))/(C_(2))` `(q_(1))/(q_(2))=(C_(1))/(C_(2))=2` or `q_(1)=2q_(2)` SOLVING, we get `q_(1)=(4Q)/(3), q_(2)=(2Q)/(3)` Charge flown through `K` is `-(Q)/(2)-(-q_(1))- -(Q)/(2)+(4Q)/(3)=5Q//6` |
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