InterviewSolution
Saved Bookmarks
| 1. |
Three moles of an ideal gas at `127^(@)C` expands isothermally untill the volume is doubled. Calculate the amount of work done and heat absorbed. |
|
Answer» Correct Answer - `6912 J, 6912 J` Here, `n=3, V_(2)= 2V_(1), dW= ?, dQ=?` As the process is isothermal, therefore, `dW= nRT "log"_(e)((V_(2))/(V_(1)))` `=3xx8.31(127+273)log_(e)2` `=3xx8.31xx400xx0.6931= 6912J` `dQ= dU+dW` `= 0+6912= 6912J` |
|