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Three moles of an ideal gas kept at a constant temperature of `300K` are compressed from a volume of 4 litre to 1 litre. Calculate work done in the process. `R= 8.31 J mol e^(-1)K^(-1)`. |
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Answer» Here, `n=3, T= 300K, V_(1)= 4` litre, `V_(2)= 1 litre, W=?` In an isothermal process, work done is `W= 2.3026 nRT"log"_(10)(V_(2))/(V_(1))` `=2.3026xx3xx8.31xx300 log_(10)(1//4)` `W= -1.037xx10^(4)J` |
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