Three numbers are chosen at random from numbers 1 to 30. The probability that the minimum of the chosen numbers is 9 and maximum is 25, isA. `(1)/(406)`B. `(1)/(812)`C. `(3)/(812)`D. none of these

Three numbers are chosen at random from numbers 1 to 30. The probabili

1.	Three numbers are chosen at random from numbers 1 to 30. The probability that the minimum of the chosen numbers is 9 and maximum is 25, isA. `(1)/(406)`B. `(1)/(812)`C. `(3)/(812)`D. none of these
Answer» Correct Answer - C Out of first 30 natural numbers, three natural numbers can be chosen in `.^(30)C_(3)` ways. If the minimum and maximum of the numbers chosen are 9 and 25 respectively, then we have to select a number from the remaining 15 numbers i.e. 10,11,..,.., 24. `therefore` Favourable number of elementary events `= .^(15)C_(1)`. Hence, required probability `=(.^(15)C_(1))/(.^(30)C_(3))=(3)/(812)`

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Three numbers are chosen at random from numbers 1 to 30. The probability that the minimum of the chosen numbers is 9 and maximum is 25, isA. `(1)/(406)`B. `(1)/(812)`C. `(3)/(812)`D. none of these

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