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Three numbers are chosen from 1 to 20. Find the probability that theyare consecutive.A. `(186)/(190)`B. `(187)/(190)`C. `(188)/(190)`D. `(18)/(.^(20)C_(3))` |
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Answer» Correct Answer - B (b) Since, the set of three consecutive numbers from 1 to 20 are 123, 234, 345,…..,18, 19, 20 i.e., 18. `"P(numbers are consecutive)"=(18)/(.^(20)C_(3))=(18)/(1140)=(3)/(190)` `"P(three numbers are not consecutive)"=1-(3)/(190)=(187)/(190)` |
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