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Three particles A, B and C move in a circle of radius `r=(1)/(pi)`m, in anti-clockwise direaction with speed `1ms^(-1), 2.5ms^(-1)` and `2ms^(-1)` respectively. The initial position of A, B and C are as shown in figure. The ratio of distance travelled by B and C by the instant A, B and C meet for the first time isA. `3:2`B. `5:4`C. `3:5`D. `3:7` |
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Answer» Correct Answer - B `(d_(B))/(d_(C))=(v_(B^(t)))/(v_(C^(t)))=(v_(B))/(c_(C))=(2.5)/(2)=(5)/(4)` |
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