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Three particles each of mass `m` are kept at vertices of an equilateral triangle of side L. The gravitational field at centre due to these particle isA. zeroB. `(Gm^(2))/(a^(2))`C. `(2Gm^(2))/(a^(2))`D. `(3Gm^(2))/(a^(2))` |
Answer» Correct Answer - a `V=-(GM)/(r//2)-(GM)/(r//2)=-(4GM)/(r)` |
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