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Three particles of masses 2 kg, 4 kg and 6 kg are located at the vertices of an equilateral triangle of side 0.5 m. What is the position of centre of mass if the origin is located at 2 kg mass and 4 kg mass located along x-axis ? |
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Answer» 0.29 m, 0.22 m `vecx=(2xx0+4xx0.5+6xx0.25)/(12)` = 0.29 m ALSO `y_(1)=y_(2)=0,y_(3)=0.5sin60^(@)=0.433m` `vecy=(2xx0+4xx0+6xx0.433)/(12)=0.22m`
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