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Three particles of the same mass lie in the x-y plane. The (x, y) coordinates of their positions are (1, 1), (2, 2) and (3, 3) respectively. The (x, y) co-ordinates of the centre of mass are: |
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Answer» (1, 2) `x=(mxx1+mxx2+mxx3)/(m+m+m)=(1)/(3)(1+2+3)=2` Similarly, `y=(mxx1+mxx2+mxx3)/(3M)=(1)/(3)(1+2+3)=2` |
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