1.

Three perfect gases at absolute temperatures T_(1), T_(2) and T_(3) are mixed. The masses of molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no less of energy, the final temperature of the mixture is:

Answer»

`(n_(1)T_(1)+n_(2)T_(2)+n_(3)T_(3))/(n_(1)+n_(2)+n_(3))`
`(n_(1)T_(1)^(2)+n_(2)T_(2)^(2)+n_(3)T_(3)^(3))/(n_(1)T_(1)+n_(2)T_(2)+n_(3)T_(3))`
`(n_(1)^(2)T_(1)^(2)+n_(2)^(2)T_(2)^(2)+n_(3)^(3)T_(3)^(3))/(n_(1)T_(1)+n_(2)T_(2)+n_(3)T_(3))`
`((T_(1)+T_(2)+T_(3)))/(3)`

Solution :If atomicity of gas is same
`(F)/(2)(n_(1)+n_(2)+n_(3))KT =(f)/(2)n_(1)kT_(1)+(f)/(2)kT_(2)+(f)/(2)n_(3)kT_(3)`
`therefore T=(n_(1)T_(1)+n_(2)T_(2)+n_(3)T_(3))/(n_(1)+n_(2)+n_(3))`
Correct choice : (a).


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