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Three perfect gases at absolute temperatures T_(1), T_(2) and T_(3) are mixed. The masses of molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no less of energy, the final temperature of the mixture is: |
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Answer» `(n_(1)T_(1)+n_(2)T_(2)+n_(3)T_(3))/(n_(1)+n_(2)+n_(3))` `(F)/(2)(n_(1)+n_(2)+n_(3))KT =(f)/(2)n_(1)kT_(1)+(f)/(2)kT_(2)+(f)/(2)n_(3)kT_(3)` `therefore T=(n_(1)T_(1)+n_(2)T_(2)+n_(3)T_(3))/(n_(1)+n_(2)+n_(3))` Correct choice : (a). |
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