Three persons P_(1), P_(2) and P_(3) are at different points A, B and C, respectively as shown in the figure. Two persons P_(1) and P_(3) clap at the same time. Which among the following can be the minimum distance between P_(2) and P_(3) to hear the clap sound distinctly by P_(2)? (Take the velocity of sound in air as 330 ms^(-1))

Three persons P_(1), P_(2) and P_(3) are at different points A, B and

1.	Three persons P_(1), P_(2) and P_(3) are at different points A, B and C, respectively as shown in the figure. Two persons P_(1) and P_(3) clap at the same time. Which among the following can be the minimum distance between P_(2) and P_(3) to hear the clap sound distinctly by P_(2)? (Take the velocity of sound in air as 330 ms^(-1))
Answer» <P>330 m 384 m 363 m 660 m Solution :Velocity of sound `'v' = 330 MS^(-1)` distance between `P_(1)` and `P_(2) = 330 m` So, time taken to hear the sound `t = (330)/(330) = 1 s` Human ear can hear TWO sounds separately only if they reach at interval of 1/10 of a second. So, the time taken by the sound from `P_(3)` to reach `P_(2)` is minimum of `1 + 1/10 = 1.1 s`. So, the distance between `P_(2)` and `P_(3) = t xx v` `= 1.1 xx 330 = 363 m.`