1.

Three persons P_(1), P_(2) and P_(3) are at different points A, B and C,as shown in the figure.P_(1) and P_(2) clap at the same time.For P_(3) to hear two distinct claps, the minimum distance betweenl P_(1) and P_(2) should be ______ m. (The velocity of sound in air is 330 ms^(-1))

Answer»

33
330
363
660

Solution :Human ear can hear two sounds separately only if they reach the ear after an INTERVAL of 1/10 of a second. So, the time taken by the sound from `P_(1)` to `P_(2)` should be GREATER than `1//10 s = 0.1 s.`
The distance between `P_(1)` and `P_(2)`
`= v XX t = 330 xx 0.1 = 33 m.`


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