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Three point masses of `1 kg, 2kg and 3 kg` lie at `(1,2), (0,-1) and (2, -3)` respectively. Calculate the co-ordinates of the centre of mass of the system. |
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Answer» Here `m_(1) = 1 kg, m_(2) = 2 kg, m_(3) = 3 kg` `x_(1) = 1, y_(1) = 2 , x_(2) = 0, y_(2) =- 1`, `x_(3) = 2, y_(3) =- 3` Co-ordinates of centre of mass `(x,y)` are given by `x = (m_(1)x_(1) + m_(2)x_(2) + m_(3)x_(3))/(m_(1) + m_(2) + m_(3))` `= (1(1) + 2(0) + 3(2))/(1 + 2+ 3) = (7)/(6)` `y = (m_(1)y_(1) + m_(2)y_(2) + m_(3)x_(3))/(m_(1) + m_(2) + m_(3))` `= (1(2) + 2(-1) + 3(-3))/(1 + 2+ 3) = (-3)/(2)` |
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